Q. [+1]
f(x) = x! × 2x
f(4) =
___________
p∆k3 c4c∆ ![]()
f(x) = x! × 2x
f(4) =
___________
p∆k3 c4c∆
Penjelasan dengan langkah-langkah:
f(x) = x! × 2x
f(4) = 4! × 2.4
f(4) = (4.3.2.1) × 8
f(4) = 24 × 8
f(4) = 192
Diketahui:
f(x) = x! × 2x
Ditanya:
f(4) = ... ?
Jawab:
f(x) = x! × 2x
f(4) = 4! × 2(4)
f(4) = (4 × 3 × 2) × 8
f(4) = 24 × 8
f(4) = 192
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